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288x^2-450=0
a = 288; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·288·(-450)
Δ = 518400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{518400}=720$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-720}{2*288}=\frac{-720}{576} =-1+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+720}{2*288}=\frac{720}{576} =1+1/4 $
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